Alright, so i gave back the inverter to the friend i was borrowing it from so no more data while driving down the road

. (until i break down and spend the $15 to get on lol)..
So i decided to just do it while it was sitting there after i had warmed up the engine. i'm putting some pictures in here of the actual reading from the car as well.
Idling: :814 RPM = .43 lb/min air intake
:1500 RPM = .60
:2000 RPM = .84
:2600 RPM = 1.30 (I was doing increments of 500rpm from the dash but the computer said this so i went with the computer)
:3100 RPM = 1.60
:3600 RPM = 2.07
:4000 RPM = 2.50
:4557 RPM = 11.22 (this is where the limiter kicks in so i just pushed my foot all the way to the floor for 10 seconds till it bounced around and hit this peak)
Now what you do is multiply the
lb/min by
13.35345 to get the
CFM, then you multiply the
CFM by
28.32 to get the
LPMso the bottem line is that if you are sitting there idling with no load, (i just realized that there is a load sensor in there! i'll have to redo this soon lol) well in the picture at idle it says 29% load. So you are sitting there at 29% load doing :814 RPM sucking in .43 lb/min of air, meaning you are using 153LPM then take into account that you only need a 34:1 A/F and you get the calculation that at idle you need
4.5lpm HHo to idle the car!! And 27.81LPM to do everything you want, 100% HHO!!
alright so lets figure out if that is plausible;
A generator that is 2hp will put out 800 steady rated watt's.
the car i am using is a "2000 Ford Contour SE 2.5-liter 170-hp, 130amp alternator"
to get 28LPM you need 280amps @ 14.7volts = 4116watt
taking the 4116 and dividing it by the efficacy of a generator (the only thing i really have to go off for
efficacy), you get 10.29hp needed to produce the needed LPM of HHO.
this all boils down to the fact that it should be more than easy to produce enough HHO from the vehicle to power it with no issues!!
steve