Hydroxy Hut
May 20, 2012, 03:01:45 pm *
Welcome, Guest. Please login or register.
Did you miss your activation email?

Login with username, password and session length
News: Hydroxy Hut discovered!
 
   Home   Help Search Login Register  
Pages: [1]
  Print  
Author Topic: Some Electronic Formulas.  (Read 689 times)
Bob
Administrator
Hero Member
*****
Posts: 3087



« on: July 16, 2008, 04:36:59 pm »

Here are some electric formulas I use.
....
P=Power in watts....I= Amps...E= Voltage...R=Resistance in Ohms
....
For Voltage
E=I.R   I=E/R   R=E/I

For  Watts...
P=I.E    I=P/E    E=P/I

Keep in mind School has been a LOOOONG time ago !
<GRIN>
Bob...
Logged

"Mother always told me "Son the Imposable is only a little bit harder"...and You know ... She WAS RIGHT!"
Bob
Administrator
Hero Member
*****
Posts: 3087



« Reply #1 on: July 16, 2008, 11:53:14 pm »

Here is an EXELENT Post by a guy on HydrogenGenerator.com
right from the text book...
 Puts my Post to shame  so Use this !
....

Circuits
7-10-00

Section 19.1

Series circuits
A series circuit is a circuit in which resistors are arranged in a chain, so the current has only one path to take. The current is the same through each resistor. The total resistance of the circuit is found by simply adding up the resistance values of the individual resistors:

equivalent resistance of resistors in series : R = R1 + R2 + R3 + ...



A series circuit is shown in the diagram above. The current flows through each resistor in turn. If the values of the three resistors are:



With a 10 V battery, by V = I R the total current in the circuit is:

I = V / R = 10 / 20 = 0.5 A. The current through each resistor would be 0.5 A.

Parallel circuits
A parallel circuit is a circuit in which the resistors are arranged with their heads connected together, and their tails connected together. The current in a parallel circuit breaks up, with some flowing along each parallel branch and re-combining when the branches meet again. The voltage across each resistor in parallel is the same.

The total resistance of a set of resistors in parallel is found by adding up the reciprocals of the resistance values, and then taking the reciprocal of the total:

equivalent resistance of resistors in parallel: 1 / R = 1 / R1 + 1 / R2 + 1 / R3 +...



A parallel circuit is shown in the diagram above. In this case the current supplied by the battery splits up, and the amount going through each resistor depends on the resistance. If the values of the three resistors are:



With a 10 V battery, by V = I R the total current in the circuit is: I = V / R = 10 / 2 = 5 A.

The individual currents can also be found using I = V / R. The voltage across each resistor is 10 V, so:

I1 = 10 / 8 = 1.25 A
I2 = 10 / 8 = 1.25 A
I3=10 / 4 = 2.5 A

Note that the currents add together to 5A, the total current.

A parallel resistor short-cut
If the resistors in parallel are identical, it can be very easy to work out the equivalent resistance. In this case the equivalent resistance of N identical resistors is the resistance of one resistor divided by N, the number of resistors. So, two 40-ohm resistors in parallel are equivalent to one 20-ohm resistor; five 50-ohm resistors in parallel are equivalent to one 10-ohm resistor, etc.

When calculating the equivalent resistance of a set of parallel resistors, people often forget to flip the 1/R upside down, putting 1/5 of an ohm instead of 5 ohms, for instance. Here's a way to check your answer. If you have two or more resistors in parallel, look for the one with the smallest resistance. The equivalent resistance will always be between the smallest resistance divided by the number of resistors, and the smallest resistance. Here's an example.

You have three resistors in parallel, with values 6 ohms, 9 ohms, and 18 ohms. The smallest resistance is 6 ohms, so the equivalent resistance must be between 2 ohms and 6 ohms (2 = 6 /3, where 3 is the number of resistors).

Doing the calculation gives 1/6 + 1/12 + 1/18 = 6/18. Flipping this upside down gives 18/6 = 3 ohms, which is certainly between 2 and 6.

Circuits with series and parallel components
Many circuits have a combination of series and parallel resistors. Generally, the total resistance in a circuit like this is found by reducing the different series and parallel combinations step-by-step to end up with a single equivalent resistance for the circuit. This allows the current to be determined easily. The current flowing through each resistor can then be found by undoing the reduction process.

General rules for doing the reduction process include:


Two (or more) resistors with their heads directly connected together and their tails directly connected together are in parallel, and they can be reduced to one resistor using the equivalent resistance equation for resistors in parallel.

Two resistors connected together so that the tail of one is connected to the head of the next, with no other path for the current to take along the line connecting them, are in series and can be reduced to one equivalent resistor.
Finally, remember that for resistors in series, the current is the same for each resistor, and for resistors in parallel, the voltage is the same for each one.
...
THANK YOU...aces2kings1966
...
Bob.....
Logged

"Mother always told me "Son the Imposable is only a little bit harder"...and You know ... She WAS RIGHT!"
Cowboy
Full Member
***
Posts: 143


« Reply #2 on: October 30, 2008, 09:54:06 am »

For any of you wanting to get more in depth, or those of you smart people that want to refresh yourself, go buy this book:

http://www.amazon.com/tag/electronics%20theory/glance

My Pops bought me one back in HS and I still open it up for reference and correction.  Good stuff
Logged
KF-Puffin1
Jr. Member
**
Posts: 58



« Reply #3 on: October 30, 2008, 11:07:11 am »

 


« Last Edit: October 30, 2008, 07:55:08 pm by KF-Puffin1 » Logged

There are those that lead , And those who follow. My wife says i must follow , and hold her purse....."sigh"
Cowboy
Full Member
***
Posts: 143


« Reply #4 on: October 30, 2008, 02:17:14 pm »

If you want to up your amps but keep voltage the same (adding a second battery to your car) you would hook pos-pos and neg-neg. 


Word.... Cheesy
« Last Edit: October 31, 2008, 07:00:23 am by Cowboy » Logged
KF-Puffin1
Jr. Member
**
Posts: 58



« Reply #5 on: October 30, 2008, 07:55:43 pm »

yea i agree, so i changed it.
Logged

There are those that lead , And those who follow. My wife says i must follow , and hold her purse....."sigh"
hydrotinkerer
Sr. Member
****
Posts: 338



« Reply #6 on: October 30, 2008, 08:13:21 pm »

You guys probably seen this before, but it comes in handy sometimes.

Amps x Volts = Watts
Watts / 745.7 (one HP) = Electrical HP Produced by the Alternator
HP x 15% Efficiency Loss = HP Loss
HP + HP Loss = Total HP Used

Example:
57A x 14.9V = 849.3 Watts
849.3 Watts / 745.7 = 1.14 HP
1.14 HP x 15% = 0.17 HP
1.14 + 0.17 = 1.31 HP Total
Logged
Pages: [1]
  Print  
 
Jump to:  

Powered by MySQL Powered by PHP Powered by SMF 1.1.10 | SMF © 2006-2009, Simple Machines LLC Valid XHTML 1.0! Valid CSS!